Find the four numbers in A.P whose sum is 50 and the product of the extremes is 100
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let the numbers be a , a + d , a + 2d , a + 3d...
4a + 6d = 50.....
a ( a + 3d ) = 100...
a = 20 & a = 5 ...
so if a= 20 then d is -5 & if a = 5 then d = 5...
hence 4 no. are ....
20, 15 , 10 ,5 ...or 5 , 10, 15, 20.....
4a + 6d = 50.....
a ( a + 3d ) = 100...
a = 20 & a = 5 ...
so if a= 20 then d is -5 & if a = 5 then d = 5...
hence 4 no. are ....
20, 15 , 10 ,5 ...or 5 , 10, 15, 20.....
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