Question

Find the four numbers in Ap such that the sum of 2nd and 3rd terms is 22
and the product of 1st and 4th terms is 85

Answer 1

Step-by-step explanation:

let the tour terms of AP be a-3d;a-d;a+d;a+3d.for easy calculation such values are assumed. These are in AP whose difference is 2d . If they give three consecutive terms we can use a-d;a;a+d....

given

2nd term +3rd term = 22

a-d+a+d=22

2a=22

a=11

also given

1st term × 4th term =85

(a-3d)×(a+3d)=85

a^2-9d^2=85

121-9d^2=85. as(a=11)

9d^2=36

d^2=4

d=2

:the numbers are 5,9,13,17