Question

find the fourth term of the following arithmetic progression root 2, root 8, root 18​

Answer 1

Step-by-step explanation:

$a = t1 = \sqrt{2} \\ t2 = \sqrt{8} = 2 \sqrt{2} \\ t3 = \sqrt{18} = 3 \sqrt{2} \\ \\ d = t2 - t1 = 2 \sqrt{2} - \sqrt{2} \\ = \sqrt{2} (2 - 1) = \sqrt{2} \\ tn = a + (n - 1)d \\ t4 = \sqrt{2} + 3( \sqrt{2} ) \\ t4 = 4 \sqrt{2} = \sqrt{32} \\ \\ \\ hope \: it \: helps \: uh$