find the fourth term the end in a a.p -11,-8,-5,.....,49
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since we have,
first term of an a.p = -11
common difference = -8-(-11) = -8+11 = 3
therefore,
t4 = a+(n-1)d = -11 + (4-1)3 = -11 + 9 = -2
hence the fourth term of an a.p is -2
first term of an a.p = -11
common difference = -8-(-11) = -8+11 = 3
therefore,
t4 = a+(n-1)d = -11 + (4-1)3 = -11 + 9 = -2
hence the fourth term of an a.p is -2
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