Question

Find the frequency of a photon when an electron of 20 Kev is brought to rest in collision with a
heavy nucleus. (h=6.63x10-34 Iš)
(1997;S)
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Answer 1

Answer:

4.48 × 10 power 18

Explanation:

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Answer 2

Answer:

E(intil)=E(final)

K+mc^2=hv+mc^2

K=hv

20*10^3ev=(4.136*10^-15ev.s)v

V=4.84*10^8Hz

Explanation:

V=frequency