Find the frequency of revolution of electron in 2nd Bohr orbit, if the radius and the speed of electron in that orbit is 2.14 x 10⁻¹⁰ m and 1.09 x 10⁶ m/s respectively.
(Ans : 8.11 x 10¹⁴Hz.)
Answers
Answered by
3
Bohr orbit is rather defined as a circular orbit around the nucleus of the atom.
Hence,
speed = Distance / Time
And we can according write,
v= 2πr/T
T = 2πr/v
= 2πr/v
Now , frequency is nothing but the reciprocal of time period.
Hence,
f = v/2πr = 1.09*10^6 / 2*3.14*2.14*10^-10
= 8.11*10^14 Hertz.
Hope this helps you !
For more help and online lectures comment down below if you need any help !
#Dhruvsh
Hence,
speed = Distance / Time
And we can according write,
v= 2πr/T
T = 2πr/v
= 2πr/v
Now , frequency is nothing but the reciprocal of time period.
Hence,
f = v/2πr = 1.09*10^6 / 2*3.14*2.14*10^-10
= 8.11*10^14 Hertz.
Hope this helps you !
For more help and online lectures comment down below if you need any help !
#Dhruvsh
Similar questions