Find the ratio of diameter of electron in 1st Bohr orbit to that in 4th bohr orbit.
(Ans : 1:16)
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Answered by
11
diameter = 1.06 n^2/Z ev
SO ratio = 1/4^2 =1/16
SO ratio = 1/4^2 =1/16
Answered by
3
Answer:
1 : 16
Explanation:
Given Find the ratio of diameter of electron in 1st Bohr orbit to that in 4th bohr orbit.
Given r 1 be the radius of n th Bohr’s orbit. Now we need to find the diameter of nth Bohr’s orbit. So it will be D1 : D4
We know that r 1 = Ɛo h^2 n^2 / π m e^2
Now D n = 2 r 1
Let n = 1
D 1 = 2 Ɛo h^2 1^2 / π m e^2
D 1 = = 2 Ɛo h^2 / π m e^2
Now let n = 4
D = = 2 Ɛo h^2 n^2 / π m e^2
D 4 = 2 Ɛo h^2 4^2 / π m e^2
D 4 = = 2 Ɛo h^2 16 / π m e^2
So D 1 / D 4 = = 2 Ɛo h^2 / π m e^2 / 16 (2 Ɛo h^2 / π m e^2)
Now D 1 / D 4 = 1/16
So D1 : D4 = 1 : 16
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