Question

find the frequency of sound in khz if a particle vibrancy 1800 times in 6 min​

Answer 1

$\underline{ \boxed{ \bold{ \huge{ \purple{Answer}}}}} \\ \\ \star \sf \: \boxed{\bold{\red{Given}}} \\ \\ \implies \sf \: a \: particle \: vibrates \: 1800 \: times \: in \: 6 \: min \\ \\ \implies \sf \: 6 \: min = 360 \: s \\ \\ \star \sf \: \boxed{ \bold{ \red{To \: Find}}} \\ \\ \implies \sf \: frequency \: of \: sound \: in \: kHz \: unit \\ \\ \star \sf \: \boxed{ \bold{ \red{Formula \: and \: Calculation}}} \\ \\ \implies \sf \: \pink{freq. = \frac{no. \: of \: vibration}{time} } \\ \\ \implies \sf \: f = \frac{1800}{360} = 5 \: Hz \\ \\ \huge{\star} \: \: \underline{\boxed{ \huge{ \bold{ \orange{ \sf{f = 5 \times {10}^{ - 3} \: kHz}}}}}} \: \: \huge{ \star}$

Answer 2

$\large \bf \red{GIVEN :}$

$\Longrightarrow \bf No. \: of \: vibration = 1800 \\ \\ \Longrightarrow \bf Time = 6 \: min = 360 \: sec$

$\large \bf \red{TO \: FIND :} \\ \\ \Longrightarrow \bf frequency \: of \: sound \: in \: khz$

$\large \bf \red{SOLUTION :}$

$\boxed{\bf\orange{ Frequency = \frac{No. \: of \: vibtation}{Time }}} \\ \\ \bf Freq. = \frac{1800}{360} \\ \\ \bf Freq. = 5 \: hz \\ \\ \bf 1 \: hz =1 \times {10}^{ - 3} khz$

$\large\underline{ \boxed{\bf \green{ Frequency = 5 \times {10}^{ - 3} khz}}}$