Question

Find the friction force (centripetal force) on a 2000 kg taking a 6 m radius turn with 5 m/s speed.

A. N 400
B. N 5666
C . 8333

Answer 1

GiveN :-

• Mass is 2000 kg .
• Radius is 6 m .
• Velocity is 5m/s .

To FinD :-

• The frictional force ( Centripetal ) .

SolutioN :-

Substitute upon the respective values in the formula of Centripetal force .

$\sf\dashrightarrow \pink{ Centripetal_{(force)}=\dfrac{mv^2}{r} }\\\\\sf\dashrightarrow F = \dfrac{(2000 kg)(5m/s)^2}{6 m } \\\\\sf\dashrightarrow F =\dfrac{2000 kg \times 25 }{6 m }\\\\\sf\dashrightarrow\underset{\blue{\sf Required \ Answer }}{\underbrace{\boxed{\pink{\frak{ F = 8333.33 Newtons }}}}}$

Answer 2

GiveN :-

• Mass is 2000 kg .
• Radius is 6 m .
• Velocity is 5m/s .

To Find :-

• The frictional force

SolutioN :-

Substitute upon the respective values in the formula of Centripetal force .

=> F = mv²/r

=> F = 5000 kg * (5m/s)² / 6m

=> F = 5000 kg * 25 m²/s² / 6m

=> F = 8333.33 N