Question

find the fundamental period of signal for x(n) = e^j7. 351*pi*n​

Answer 1

Answer:

Zzhxjxjxjcjuxjcjsjzjxh

Explanation:

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Answer 2

Answer:

N=2000

Explanation:

e^j7. 351*pi*(n​+N)= e^j7. 351*pi*n​ * e^j7. 351*pi*N

e^j7. 351*pi*N =1 MUST

e^j7. 351*pi*N = COS 7. 351*pi*N +j SIN 7. 351*pi*N= 1

7. 351*pi*N= COS^-1 (1)=m*2*pi, m= 1,2,3 ,4

N=2000 m/7351

so at m = 7351

N=2000