Question

Find the G.C.D. of ( a - b )³- ( a - b )³​

Answer 1

Answer:

I hope it helps u

Step-by-step explanation:

First expression = a2b + ab2

= ab(a + b)

= a × b × (a + b)

Second expression = a2c + abc

= ac(a + b)

= a × c × (a + b)

It can be seen, in both the expressions ‘a’ and ‘(a + b)’ are the common factors and there is no other common factor.

Therefore, the required G.C.S. a2b + ab2 and a2c + abc is a(a + b)

Answer 2

Answer:

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Step-by-step explanation:

We first factorize the given polynomials (a−1)5(a+3)2 and (a−2)2(a−1)3(a+3)4 as shown below:

(a−1)5(a+3)2=(a−1)⋅(a−1)⋅(a−1)⋅(a−1)⋅(a−1)⋅(a+3)⋅(a+3)⋅(a+3)

(a−2)2(a−1)3(a+3)4=(a−2)⋅(a−2)⋅(a−1)⋅(a−1)⋅(a−1)⋅(a+3)⋅(a+3)⋅(a+3)⋅(a+3)

The common factors of (a−1)5(a+3)2 and (a−2)2(a−1)3(a+3)4 are (a−1)3 and (a+3)2, therefore, the GCD is (a−1)3(a+