Find the g.p in which second terms is root 6 and 6th term is 9 root
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We know that the formula for the nth term of an G.P is Tn=arn−1, where a is the first term, r is the common ratio.
It is given that the 2nd term is T2=6, therefore,
T2=ar2−1⇒6=ar⇒a=r6.....(1)
It is also given that the 6th term is T6=96, therefore using equation 1,
T6=ar6−1⇒96=r6×r5⇒696=r4⇒r4=9⇒(r2)2=32⇒r2=
Step-by-step explanation:
Hope IT will help you.....
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