Question

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Answer 1

$\sf {LHS = \dfrac{cos \ \theta }{1 - sin \ \theta} }\\\\\\\sf {= \dfrac{cos^{2} \ \theta}{cos \ \theta (1 - Sin \ \theta)}}\\\\\\\sf {= \dfrac{1 - sin^{2} \ \theta}{cos \ \theta (1-sin \ \theta)}}\\\\\\\sf {= \dfrac{(1-sin \ \theta )(1+sin \ \theta)}{cos \ \theta (1-sin \ \theta)}}\\\\\\\sf {= \dfrac{1+sin \ \theta }{cos \ \theta} = RHS}$

Hence Proved

Answer 2

Answer:

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Explanation:

LHS=

1−sin θ

cos θ

=

cos θ(1−Sin θ)

cos

2

θ

=

cos θ(1−sin θ)

1−sin

2

θ

=

cos θ(1−sin θ)

(1−sin θ)(1+sin θ)

=

cos θ

1+sin θ

=RHS