Question

find the gcd(a+b,a-b)​

Answer 1

Answer:

I don't know bro

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Answer 2

Answer:

I want to show that for gcd(a,b)=1 a,b∈Z gcd(a+b,a−b)=1 or gcd(a+b,a−b)=2 holds.

I think the first step should look something like this:

d=gcd(a+b,a−b)=gcd(2a,a−b)

From here I tried to proceed with two cases.

1: a−b is even, which leads to gcd(a+b,a−b)=2

2: a−b is odd, which leads to gcd(a+b,a−b)=1

My main problem I think is, that I do not know how I should include gcd(a,b)=1 in the proof.

Any help is appreciated. Thx in advance.

Cherio Woltan

Step-by-step explanation:

I hope you correct answer