Math, asked by ksvarshaksvarsha, 4 months ago

Find the GCD of 25bc ^4d^3,35b^2c^2,45c^3d​

Answers

Answered by anshumanmisha917
1

25bc4 d3 = 5 × 5 × b × c3 × c × d3

35b2c5 = 5 × 7 × b × 2 × c3 × c2

45c3 d = 5 × 3 × 3 × c3 × d

Greatest common divisor = 5c3

25bc4 d3 = 5 × 5 × b × c3 × c × d3

35b2c5 = 5 × 7 × b × 2 × c3 × c2

45c3 d = 5 × 3 × 3 × c3 × d

Greatest common divisor = 5c3

25bc4 d3 = 5 × 5 × b × c3 × c × d3

35b2c5 = 5 × 7 × b × 2 × c3 × c2

45c3 d = 5 × 3 × 3 × c3 × d

Greatest common divisor = 5c3

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