find the general (nth term) and 23rd term of the sequence 3,1,-1,-3.......
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Answered by
35
a =3
d = 1-3
= -2
T23 =a + 22d
= 3 + 22(-2)
=3 -44
=-41
d = 1-3
= -2
T23 =a + 22d
= 3 + 22(-2)
=3 -44
=-41
Answered by
7
Answer:
A =3
d = 1-3
= -2
T23 =a + 22d
= 3 + 22(-2)
=3 -44
=-41
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