find the general solution of cos 3x + cos x - cos2x
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Answer:
cos2x=2cos2x−1cos3x=4cos3x−3cosx
cosx−cos2x+cos3x=0
cosx−(2cos2x−1)+(4cos3x−3cosx)=0
4cos3x−2cos2x−2cosx+1=0
2cos2x(2cosx−1)−1(2cosx−1)=0
(2cosx−1)(2cos2x−1)=0
cosx=12⟹x=±π3+2πn
cosx=±12–√⇒x=π4+π2n
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Answer:
Step-by-step explanation:Answer:
cos2x=2cos2x−1cos3x=4cos3x−3cosx
cosx−cos2x+cos3x=0
cosx−(2cos2x−1)+(4cos3x−3cosx)=0
4cos3x−2cos2x−2cosx+1=0
2cos2x(2cosx−1)−1(2cosx−1)=0
(2cosx−1)(2cos2x−1)=0
cosx=12⟹x=±π3+2πn
cosx=±12–√⇒x=π4+π2n
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