find the general solution of sin(x+pie/12)=0
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Answered by
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Step-by-step explanation:
MARK BRAINLEST
The solution of the equation is x=\frac{12n\pi-\pi}{12}x=
12
12nπ−π
.
Step-by-step explanation:
Given : Equation \sin(x+\frac{\pi}{12})=0sin(x+
12
π
)=0
To find : The general solution of the equation ?
Solution :
The general solution of \sin x=0sinx=0 is x=n\pix=nπ where n∈I.
So, the solution of the equation \sin(x+\frac{\pi}{12})=0sin(x+
12
π
)=0 is
x+\frac{\pi}{12}=n\pix+
12
π
=nπ
x=n\pi-\frac{\pi}{12}x=nπ−
12
π
x=\frac{12n\pi-\pi}{12}x=
12
12nπ−π
Therefore, the solution of the equation is x=\frac{12n\pi-\pi}{12}x=
12
12nπ−π
.
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