Question

Find the general solution of sin2x+son4x+sin6x=0

Answer 1

Step-by-step explanation:

sin6x+sin2x+sin4x=0

2sin4xcos2x+sin4x=0

sin4x(2cos2x+1)=0

sin4x=0 or 2cos2x+1=0

4x=nΠ. or cos2x=-1/2

x=nΠ/4 or cos2x=cos(Π+Π/6)

cos2x=cos7Π/6

2x=2nΠ±7Π/6

x=nΠ±7Π/12