Find the general solution of sin2x+son4x+sin6x=0
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Step-by-step explanation:
sin6x+sin2x+sin4x=0
2sin4xcos2x+sin4x=0
sin4x(2cos2x+1)=0
sin4x=0 or 2cos2x+1=0
4x=nΠ. or cos2x=-1/2
x=nΠ/4 or cos2x=cos(Π+Π/6)
cos2x=cos7Π/6
2x=2nΠ±7Π/6
x=nΠ±7Π/12
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