Find the general solution of the equation , 2 + tan x · cot x/2+ cot x · tan x/2= 0
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let (1 - tan² x/2) / 2 = Z
Tan x = 2 Tan x/2 / (1 - Tan² x/2)
Cot x = (1 - tan² x/2) / (2 Tan²x/2 )
given 2 + 1 / Z + Z = 0 => Z² + 2 Z + 1 = 0 => Z = -1
1 - Tan² x/2 = -2
Tan² x/2 = 3 => x/2 = n π + π/3
general solution: x = 2 n π + 2π/3 , n = integer
Tan x = 2 Tan x/2 / (1 - Tan² x/2)
Cot x = (1 - tan² x/2) / (2 Tan²x/2 )
given 2 + 1 / Z + Z = 0 => Z² + 2 Z + 1 = 0 => Z = -1
1 - Tan² x/2 = -2
Tan² x/2 = 3 => x/2 = n π + π/3
general solution: x = 2 n π + 2π/3 , n = integer
Answered by
0
let (1 - tan² x/2) / 2 = Z
Tan x = 2 Tan x/2 / (1 - Tan² x/2)
Cot x = (1 - tan² x/2) / (2 Tan²x/2 )
given 2 + 1 / Z + Z = 0 => Z² + 2 Z + 1 = 0 => Z = -1
1 - Tan² x/2 = -2
Tan² x/2 = 3 => x/2 = n π + π/3
general solution: x = 2 n π + 2π/3 , n = integer
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