Question

Find the largest number that divides 220,313 and 716 leaving remainder 3 in each case.

Answer 1

220-3=217
313-3=310
716-3=713

By prime factorizing 217,310 and 713 we get→

 217= 7*31
310=2*5*31
713=23*31
so, the H.C.F of 217,310 and 713= 31

Hence the largest number that divides 220,313 and 716, leaving a remainder 3 in each case is 31.

Answer 2

largest no. that divides 220, 313 and 716 leaving remainder 3 in each case is 31