Math, asked by bhavya6533, 23 days ago

Find the general solution of the following equation cot2 β+ [3/sin β] +3=0? Fast please and accurate answer only. ​

Answers

Answered by jiwoo2341
1

Answer:

Correct option isAnπ+(−1) n (− 6π )Given cot 2 θ+ sinθ3 +3=0As we know that cot 2 θ=cosec 2 θ−1cosec 2 θ−1+3cosecθ+3=0⟹cosec 2 θ+3cosecθ+2=0⟹(cosecθ+2)(cosecθ+1)=0⟹cosecθ=−2 or −1So x=nπ+(−1) n

Answered by rameshprasadsrivasta
0

Answer:

and the only way I can tell if I have a problem is a lot to get

Step-by-step explanation:

6AM the darkne is the only one who can be the one to make

Similar questions