Question

find the general term and the 18th term of an AP whose first term is 3 and the common difference is 2​

Answer 1

T(r) =a+(r-1)d

T(r)=3+(r-1)2. - - - 1st ans

T(18)=3+(18-1)2

=3+34

=37. - - - 2nd ans

Answer 2

formula is

$an = a + (n - 1)d$

so a18= 3+(18-1)2

=3+17×2

=3+34

=37