Question

find the general value of 4sin⁴theta+cos⁴theta=1​

Answer 1

⭐ Answer⭐

4sin

4

α+cos

4

α=1

or4sin

4

α=1−cos

4

α

or4sin

4

α=sin

4

α

orsin

4

α(4−1)=0

orsin

4

α=∞

Answer 2

4 sin40 +cos40 =1

or, 4 [(sin20)^2+ (cos20)^2] =1

or, 4[( sin20+cos20)^2 -2sin20cos20]

or, 4(1-2sin^20cos^20)=1

or, 1-2sin20cos20 =1/4

or, 2sin20cos20 = 3/4

or, sin20cos20 = 3/8

or, sin0cos0 =root3 / 2 root2

or, 2 sin0cos0 =root3/root2

or, sin20 = root3/root2