Math, asked by pooja7646, 8 months ago

if 16 X square - 8 x + 1 is equal to zero when x is equal to 1 by 4 Y find the value of Y​

Answers

Answered by puzzlepedia
1

Answer:

Y=1

Step-by-step explanation:

16x^2-8x+1=0

16x^2-4x-4x+1=0

4x(4x-1)-1(4x-1)=0

(4x-1)(4x-1)=0

x=1/4

x=1/4y

1/4=1/4y

4y=4

y=1

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