Question

find the goemetric mean between 3/2 and 27/2

Answer 1

$let \\ {b}^{2} = ac \\ here \\ a = \frac{3}{2} and \: b = \frac{27}{2 } \\ so \\ {b}^{2} = \frac{ 3}{2} \times \frac{27}{2} \\ > > > = \frac{81}{4} \\ \\ b = \frac{9}{2}$
geometric mean is 9/2

Answer 2

Answer:

The geometric mean $\frac{3}{2}$ and  $\frac{27}{2}$ is $\frac{9}{2}$

Step-by-step explanation:

To find : The geometric mean between $\frac{3}{2}$ and  $\frac{27}{2}$ ?

Solution :

The geometric mean between number is given by

$\sqrt[n]{x_1x_2x_3..x_n}$

Where, n is the number of terms.

We have given two numbers i.e. $\frac{3}{2}$ and  $\frac{27}{2}$

The geometric mean between these two number is given by,

$GM=\sqrt{\frac{3}{2}\times \frac{27}{2}}$

$GM=\sqrt{\frac{81}{4}}$

$GM=\frac{9}{2}$

Therefore, The geometric mean $\frac{3}{2}$ and  $\frac{27}{2}$ is $\frac{9}{2}$