find the gratest 4 digit number which is exactly divisible by each of 8 , 12 and 20
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3
Step-by-step explanation:
First we find the LCM of 8,12 and 20.(Refer Fig.1)
∴ LCM of given numbers =2×2××3×5=120
According to given condition , we need a greatest number of 4 -digit which is exactly divisible by 120.
Greatest number of 4-digit =9999
We divide 9999 by 120 and find the remainder (Refer Fig.2)
∴ The required number =9999−39=9960
Answered by
0
Answer:
9960
Step-by-step explanation:
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