Question

Find the gravitational force between earth and an object of 2 kg mass placed on its surface. ( Given, mass of the earth = 6×10^24 kg and radius of the earth = 6.4 x 106 m)​​

Answer 1

Answer:

• The Gravitational force between earth and object = 19.54 N  (approx.)

Explanation:

Given

• Mass of object on Earth's surface, m = 2 kg
• Mass of Earth, M = 6 × 10^24 kg
• The Radius of Earth, R = 6.4 × 10^6 m

To find

• The Gravitational force between the Earth and Object, F =?

Formula required

• Formula to calculate Gravitational force 'F' between two bodies of masses, m and M which are at a distance of 'R' to each other.

       F = G M m / R^2

[ Where G is universal gravitation constant ]

Solution

In this condition, Object is placed at the surface of Earth. therefore the distance between them will be equal to the radius of Earth.

Using Formula to calculate Gravitational force

→  F = G M m / R^2

[ Taking the value of G as 6.67 × 10^(-11) m^3 kg^(-1) s^(-2) ]

→  F = 6.67 × 10^(-11) × 6 × 10^24 × 2 / (6.4 × 10^6)^2

→  F = 80.04 × 10^(24-11) / [ 40.96 × 10^12 ]

→ F = 1.954 × 10

→ F = 19.54 N  [Approx.]

Therefore,

• The Gravitational force between the Object and Earth would be 19.54 Newtons approximately.

Answer 2

Answer:

The Gravitational force between earth and object = 19.54 N  (approx.)

Explanation:

Given

Mass of object on Earth's surface, m = 2 kg

Mass of Earth, M = 6 × 10^24 kg

The Radius of Earth, R = 6.4 × 10^6 m

To find

The Gravitational force between the Earth and Object, F =?

Formula required

Formula to calculate Gravitational force 'F' between two bodies of masses, m and M which are at a distance of 'R' to each other.

       F = G M m / R^2

[ Where G is universal gravitation constant ]

Solution

In this condition, Object is placed at the surface of Earth. therefore the distance between them will be equal to the radius of Earth.

Using Formula to calculate Gravitational force

→  F = G M m / R^2

[ Taking the value of G as 6.67 × 10^(-11) m^3 kg^(-1) s^(-2) ]

→  F = 6.67 × 10^(-11) × 6 × 10^24 × 2 / (6.4 × 10^6)^2

→  F = 80.04 × 10^(24-11) / [ 40.96 × 10^12 ]

→ F = 1.954 × 10

→ F = 19.54 N  [Approx.]

Therefore,

The Gravitational force between the Object and Earth would be 19.54 Newtons approximately.