Question

find the gravitational force of attraction between earth (m=6*10^24 kg) and a body of mass 10 kg kept on its surface .(given r =6400 km )​

Answer 1

Answer:

F= 98.14 N

Explanation:

given

mass of earth = 6×10²⁴ kg

mass of body = 10 kg

body kept on earth surface radius of earth = 6400 km = 6400000meter

solution

by newton law of gravitation

$F=G\frac{m_{1}m_{2} }{R^{2} }$

F= 6.7×10⁻¹¹× 6×10²⁴×10/6400000²

F= 98.14 N

it also can be find by simply

f= mg

F = 10×9.8

f= 98 N

Answer 2

Answer:

Explanation:

f= mg

F = 10×9.8

f= 98 N