Question

Find the greatest 4-digit no. which is exactly divisible by each of 8,12 and 20 (with full solution)

Answer 1

Firstly we will find out the LCM of 8, 12 & 20

8= 2×2×2
12= 2×2×3
20=2×2×5
Lcm= 2××2×2×3×5= 120

Greatest 4 digit number is 9999

Then divide this number by LCM of 8, 12 & 20 9999/120 will get remainder 39

now subtract 39 from the 4 digit number
9999 – 39 = 9960

9960 is the greatest number 4-digit number divisible by 8, 12 ,&20

Answer 2

Firstly we will find out the LCM of 8, 12 & 20

8= 2×2×2

12= 2×2×3

20=2×2×5

Lcm= 2××2×2×3×5= 120

Greatest 4 digit number is 9999

Then divide this number by LCM of 8, 12 & 20 9999/120 will get remainder 39

now subtract 39 from the 4 digit number

9999 – 39 = 9960

9960 is the greatest number 4-digit number divisible by 8, 12 ,

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