Question

Find the greatest 4 digit number which when divided by 36,30,24 and 16 leaves a remainder 13 in each case

Answer 1

Explanation:

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Answer 2

Answer:

The greatest four digit number is 9347.

Explanation:

Step 1: 9999 is the 4 digit greatest number.

Step 2: LCM of 36,30,24,16.

36 30 24 16|2

18 15 12 8|2

9 15 6 4|2

9 15 3 2|3

3 5 1 2 |2

3 5 1 1|3

1 5 1 1|5

1 1 1 1

So LCM=2×2×2×2×3×3×5=720.

Step 3: Now Divide the LCM 720 to 9999.

720 ) 9999 (13

- 720

------------------

2799

- 2160

------------------

639

---------------

By division we got 639 as the remainder and 13 as the quotient.  

Step 4:

Now subtract remainder 639 from 9999

=9999-639

=9360

(OR)

Multiple 790 to the remainder 13

=790×13

=9360

Step 5: Now subtract 13 from 9360 to get a remainder which leaves 13 in each case

=9360-13

= 9347