Math, asked by pradeep55570, 11 months ago

find the greatest 4 digit nunber which when divided by 36, 30, 24 and 16 leaves a remainder 13 in each case​

Answers

Answered by Anonymous
4

Answer:

Hey friends

Good Evening

Here's your answer

Follow these steps to find the greatest 4 digit number which when divided by 36, 30, 24 and 16 leaves a remainder 13 in each case:

Step 1: First find the LCM of the greatest 4 digit number which is 9999.

And by LCM it's answer is 720.

Step 2: Now Divide the LCM 720 to 9999. By division we get 639 as the remainder and 13 as the quotient.

Step 3:Now subtract remainder 639 from 9999

=9999 - 639

=9360

( OR )

Multiple 790 to the remainder 13

=790 × 13

=9360

Step 4: Now subtract 13 from 9360 to get the 4 digit number which when divided by 36, 30, 24, and 16 leaves a remainder of 13 in each case

=9360 - 13

=9347 is the required number.

HOPE MY ANSWER HELPS YOU

HAVE A GOOD TIME

THANK YOU

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