Question

Find the greatest 4digit number which when divedby 20,25and 45 leavs a remainder of 11 in each case

Answer 1

Step-by-step explanation:

greatest 4 digits number is 9911

Answer 2

9911

Step-by-step explanation:

Factor of

$20=2\times2\times5\\25=5\times5\\45=3\times3\times5$

L.C.M = $2\times5\times2\times3\times3\times5$

         = $900$

Let the number be x

$x\times900=9999\\900x=9999\\x=\frac{9999}{900}\\x=11$

To find greatest four digit number =

$900\times11+11\\9900+11\\=9911$