find the greatest 7 digit number which is exactly divisible by 143
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Answered by
16
The greatest 7 digit number is 9999999.
9999999 = 143 x 69930 + 9
So, 9999999-9 = 9999990 is exactly divisible by 143.
Answered by
6
=> dividend - remainder
=> 9999999 - 9 = 9999990
hence , 9999990 is the greatest 7 digit number which is exactly divisible 143
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