Math, asked by sampannaashu, 4 months ago

Find the greatest four-digit number which when divided by 20, 30, 35 and
45 leaves remainder 12 in each case.
(A) 8442
(B) 8242
(C) 8832
(D) 9892
(E) None of these​

Answers

Answered by chaharvikal
2

Answer:

you can take lcm of 20,30,35,45

then divide 9999 by lcm

then minus remainder from 9999

then ans

Answered by piyush6265
4

Answer:

8832

Step-by-step explanation:

prime factor of :

20 = 2×2×5

30 = 2×3×5

35 = 5×7

45 = 3×3×5

LCM = 2×2×3×3×5×7

= 1260

Greatest four digit number = 9999

9999 - 1260 = 8739

8739 + 12 = 8832

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