Find the greatest integer which divides 42, 52, 86 leaving remainder 6, 4 and 2 respectively
Answers
Answered by
6
We need to find HCF of 42-6=36 , 52-4= 48 , 86-2 84
36= 2x2x3x3
48= 2x2x2x2x3
84= 2x2x3x7
So HCF is 12
36= 2x2x3x3
48= 2x2x2x2x3
84= 2x2x3x7
So HCF is 12
Answered by
11
Answer:
greatest integer=12
Step-by-step explanation:
42–6= 36, 52–4 = 48, 86–2= 84. We see that 36, 48 and 84 are all divisible by 2
36-2×2×3×3
48-2×2×2×2×3
84-2×2×3×7
common factors are2×2×3=12
so, greatest integer=12
Similar questions