Question

find the greatest no which devides 286 and 1250leaving reamainder 10 and 8 reaspectevely

Answer 1

answer is 23.

1)number -remainder=286-10=276

2) =1250-8=1242

276 can be written as 2*2*3*23

1242 as 2*3*3*3*23

hcf of them is 23

so when 286 is divided by 23 then remainder is 10 and 1250 div by 23 remainder is 8.