Find the greatest number of 3-digits which is exactly divisible by 40, 48 and 60. (Hint: Find the H.C.F.)
Answers
Answered by
0
Answer:
40 - 2×2×5
48 - 2×2×2×2×3
60 - 2×2×3×5
HCF - 2×2 = 4
Answered by
0
Answer:
The greatest 3-digit number divisible by 40, 48 and 60 is 960. 373
Similar questions