Find the greatest number of 4-digits which is exactly divisible by 40, 48 and 60.
(lcm and hcf rule)
Answers
Answer:
Step-by-step explanation:
The answer is 9840.
This can be calculated as follows…
The factors of 40=2 * 2 * 2 * 5
48=2 * 2 * 2 * 2 * 3
The LCM of 40 and 48 is = 2 * 2 * 2 * 5 * 2 * 3 = 240
60=2 * 2 * 3 * 5
240=2 * 2 * 2 * 5 * 2 * 3
LCM of 240 and 60 is=2 * 2 * 5 * 3 * 2 * 2=240
Therefore LCM of 40, 48 and 60 is=240
If you look at the multiples of 240
240*10=2400
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240*40=9600
240*50=12000
Hence try multiplying the numbers between 40 and 50 with 240
You will find that 240*41=9840 is the largest four digit multiple of 240( 240*42 is a five digit number)
Hence 9840 is the largest four digit number which is exactly divisible by 40, 48 and 60.
( However if you consider 40 and 60 alone, then 9960 is the largest 4-digit number. But it is not exactly divisible by 48 )
Answer:
Step-by-step explanation:
Step 1:- divide four digit greatest number i.e 9999 by LCM of 40, 48,60 i.e 240 and you will get 41 as quotient and 159 as remainder.
Step 2:-subtract 159 from 9999 and u will get the answer i.e 9840