Question

Find the greatest number of 4-digits which is exactly divisible by 40, 48 and 60

Answer 1

Answer:

The required number is 9996 which is exactly divisible by 40, 48 and 60.

Step-by-step explanation:

To find : The Greatest 4-digit number exactly divisible by 40, 48 and 60?

Solution :  

The greatest 4-digit number is 9999.

Now, Find the LCM of 40, 48 and 60.

$40=2\times 2\times 5$

$48=2\times 2\times2\times 2\times 3$

$60=2\times 2\times 3\times 5$

$LCM(40,48,60)=2\times 2$

$LCM(40,48,60)=4$

Divide 9999 by 4 so that we get the remainder,

$9999 = 2499\times4 + 3$

Remainder is 3.

Now, Subtract the remainder from 9999.

$9999-3=9996$

Therefore, The required number is 9996 which is exactly divisible by 40, 48 and 60.

Answer 2

Answer:

the answer is 9840

Step-by-step explanation:

The greatest number of 4 digits are 9999

taking LCM of 40,48 and 60

40=2×2×2×5

48=2×2×2×2×3

60=2×2×3×5

LCM of 40,48,60 are 240

4 digit greatest number which can divisible by 40,48 and 60 =9999÷240

divisor 240

dividend 9999

quotient 41

reminder 159

subtracting reminder from the 4 digit greatest number

taking then =9999-159= 9840

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