Math, asked by kkasu, 1 year ago

find the greatest number of 5 digits exactly divisible by 9 12 15 18 and 24

Answers

Answered by ishikajaiswal7277
217

Answer:

Greatest number of five digits divisible by 9, 12, 15, 18 and 24 = 99999 - 279 = 99720. Sol: LCM of 9, 12, 15, 18 and 24 by division method is 360. The quotient when 99999 is divided by 360 is 277 and the remainder is 279.

Answered by pinquancaro
323

Answer:

The required number is 99720 which is exactly divisible by by 9,12,15,18 and 24.                    

Step-by-step explanation:

To find : The Greatest 5 digit number exactly divisible by 9,12,15,18 and 24?

Solution :  

The greatest 5-digit number is 99999.

Now, Find the LCM of  9,12,15,18 and 24.

2 | 9  12  15  18  24

2 | 9   6  15   9   12

2 | 9   3  15   9   6

3 | 9   3  15   9   3

3 | 3   1   5    3   1

5 | 1   1   5    1   1

 | 1   1     1    1   1

LCM(9,12,15,18,24)=2\times 2\times 2\times 3\times 3\times 5  

LCM(9,12,15,18,24)=360

Divide 99999 by 360 so that we get the remainder,

99999 = 277 \times 360+279

Remainder is 279.

Now, Subtract the remainder from 99999.

99999-279=99720

Therefore, The required number is 99720 which is exactly divisible by by 9,12,15,18 and 24.

Similar questions