Question

find the greatest number of 5 digits which on being divided by 9 12 24 and 45 leaves 3 6 18 and 39 as remainders respectively

Answer 1

Answer:

remainder is same in all the cases which is 6

STEP 1:

LCM OF DIVISORS

LCM OF( 9,12,24,45) IS 360

STEP 2:

We know the largest five digit number is 99999

Now to find the largest five digit number which satisfy the given conditons then do the following

A) 360*N-6

N, is the quotient of 99999/360

U will get the answer as 360*277–6= 97214

B) Divide 99999/360

U will get remainder as 279

SUBTRACT 279 FROM 99999 WHICH IS 99720

Now 99720–6= 97214 which will be ur answer

Answer 2

Answer:

ANSWER IS 99714

Step-by-step explanation: