Question

Find the greatest number of 5 digits which when divided by 45, 60 and 75 leaves 20 as remainder in each case.​

Answer 1

Answer:

The answer is 99920.....

Explanation:

we know that the greatest number of 5 digit is

99999...

Here,

the LCM of 45 , 60 ,75 are..

$15| \frac{45}{3}. \frac{60}{4}. \frac{75}{5} |$

so, the LCM is 15×3×4×5= 900...

therefore,

the multiple of 900 nearest to 99999 and of 5 digit is...

$900 | \binom{99999}{ \frac{( - )99999}{ \times } } | 111.11$

so,

$900 \times 111$

$= 99900$

and,

$99900 + 20$

$= 99920$

this is the required answer..