find the greatest number of 6 digits exactly divisible by 15, 24,30
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Q. Find the greatest number of 6 digit exactly divisible by 15, 24, 30.
A. First, we take the LCM of 15, 24 and 30.
= 120.
Greatest 6 digit number = 999999.
Now, let us divide the greatest 6 digit number by the LCM.
We get quotient and 8333 and remainder as 39.
Therefore, greatest 6 digit number divisible by 15, 24 and 30 = 999999 - 39
= 999960.
Thanks and have a great day! :)
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