Question

the area of a square field is 5184 millimetre square. find the area of a rectangular field whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth

Answer 1

Given, that

the area of square is=5184m²

s×s=5184

s²=5184

s=√5184

s=72

according to problem,

l=2x

b=x

we know that,
perimeter of square=perimeter of rectangle

4s=2(l+b)
4×72=2(2x+x)
288=6x
x=288/6

x=48
put the value of x then

l=2x
=2×48
=96
b=x
=48

then length is 96 , breadth is 48

area of rectangle = l × b
= 96 × 48
=4608 m² ans

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Answer 2

Here is your solution

Given :-

Area of square = 6889 m^2

we have to find perimeter of square =?

Now

Area of square = side^2

=>5184 m^2 = side^2

=>72m =side of square

Now

perimeter of square => 4× side .
=> 4×72=288m

Now,

Let,
The breadth of rectangle be x

Then the length be 2x

As we know that,

 perimeter of a rectangle =2(length+breadth)

And, perimeter of square = perimeter of rectangle = 288m 

288 = 2(x + 2x)

288/2 = 3x

144 = 3x

144/3 =x

48 = x

Then,

breadth of rectangle = x = 48 m 

and length of rectangle = 2x = (2×48) = 96m 

Now,

Area of rectangle = length×breadth

Here,

Area of rectangle =  48×96 

Area of rectangle =4608 m^2

Hopeit helps you