find the greatest number of 6 digits which is a perfect square find the square root of this number
Answers
Answer:
998,001
Step-by-step explanation:
Let x² be the largest six-digit perfect square.
The largest six-digit number is 999,999, so
x² ≤ 999,999.
You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)².
(1,000 - 1)² = 999² = 998,001.
.
Method 2 :
We know the greatest number of 6 digits is 999999.
Then solving through division method,
We get quotient as 999.99 So it is not a perfect square.
But if we consider it to be as (1000-1)² which will be equal to 999².
(1000 - 1)² = 999² = 998001
.·.The greatest 6 digit number which is a perfect square is 998001.
Answer:
So the largest 6-digit number that is a perfect is 998001 and its square root is 999.
Hope it's help you.....