Math, asked by vickykant, 11 months ago

find the greatest number of 6 digits which is a perfect square find the square root of this number​


Anonymous: ___k off

Answers

Answered by gauravy
2

Answer:

998,001

Step-by-step explanation:

Let x² be the largest six-digit perfect square.

The largest six-digit number is 999,999, so

x² ≤ 999,999.

You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)².

(1,000 - 1)² = 999² = 998,001.

.

Method 2 :

We know the greatest number of 6 digits is 999999.

Then solving through division method,

We get quotient as 999.99 So it is not a perfect square.

But if we consider it to be as (1000-1)² which will be equal to 999².

            (1000 - 1)² = 999² = 998001

.·.The greatest 6 digit number which is a perfect square is 998001.

Answered by kanchisingh66
1

Answer:

So the largest 6-digit number that is a perfect is 998001 and its square root is 999.

Hope it's help you.....

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