if the sum of first 8 and 19 terms are 64 and 361 respectively.find the (1) common difference (2)sum of n terms of the series
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Answer:
• Sum of n terms in AP :
Sn = (n/2)[2a + (n- 1)d]
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⇒ S₈ = 64
⇒ 8/2 × (2a + 7d) = 64
⇒ 4 × (2a + 7d) = 64
⇒ 2a + 7d = 16 — eq. ( I )
⇒ S₁₉ = 361
⇒ 19/2 × (2a + 18d) = 361
⇒ 19 × (a + 9d) = 361
⇒ a + 9d = 19 — eq. ( II )
• Multiplying eq.( II ) by 2 & Subtracting from eq.( I ) from eq.( II ) :
↠ 2a + 18d - 2a - 7d = 38 - 16
↠ 11d = 22
↠ d = 2
• Substitute d value in eq. ( II ) :
⇒ a + 18 = 19
⇒ a = 19 - 18
⇒ a = 1
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⋆ Sum of nth terms of the AP :
↠ Sn = n/2 [2a + (n - 1)d]
↠ Sn = n/2 × [2 × 1 + (n - 1) × 2]
↠ Sn = n/2 × [2 + 2n - 2]
↠ Sn = n/2 × 2n
↠ Sn = n × n
↠ Sn = n²
∴ Sum of nth terms of the AP is n².
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