find the greatest number of five digits which is divided by 3,5,8,12 leave 2 as remainder
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Answered by
0
Answer:
the greatest number divided by the given numbers is called LCM. from your question 2 is leaving in all, so have to add 2 to the LCM of given numbers.
LCM of 3,5,8,12 is 120
adding 2 = 120+2
=122
Step-by-step explanation:
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Answered by
1
Greatest number of 5 digits =99999.
L.C.M of 3,5,8 and 12.
=2×2×3×5×2
=120
Dividing 99999 by 120 the remainder =39
∴ Required number =(99999−39)+2
=99960+2=99962
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