Question

Find the greatest number of four digit exactly divisible by 12, 16, 24, 28, 36

Answer 1

Answer:

That means that 144 will fit into 9999 no more than 69 times (and 70*144=10080 is greater than 9999). Therefore, the greatest 4-digit number exactly divisible by 12, 16, 24, 28, and 36 is the product 144*69

Step-by-step explanation:

Answer 2

What is the greatest number of 4 digits exactly divisible by 12, 16, 24, 28, and 36?

The number that I came up with was 9,072. I found the LCM (Least Common Multiple) using Prime factorization which was 1,008 but you wanted the highest 4 digit number so I multiplied 1,008 to the highest whole number that would still render a 4 digit answer, which was 9 (1,008 * 9 = 9,072).

12 = 2 x 2 x 3

16 = 2 x 2 x 2 x 2

24= 2 x 2 x 2 x 3

28 = 2 x 2 x 7

36 = 2 x 2 x 3 x 3

LCM = 2 x 2 x 2 x 2 x 3 x 3 x 7 = 1,008

1,008 x 9 = 9,072

9,072 is divisible by 12(756), 16 (567), 24 (378), 28 (324), & 36(252)

I hope that it helps