Math, asked by dheerajkrsharma14, 11 months ago

find the greatest number of four digit which is exactly divisible by 15,25 and 45​

Answers

Answered by mahii178
8

Answer:

9900

Step-by-step explanation:

To find the greatest no divisible by 15,25,45 follow the steps

  1. take out the lcm of 15,25,45 = 225
  2. divide the largest 4 digit (9999) with the lcm of the given numbers (25)
  3. subtract the remainder(99) from the dividend(9999)
  4. the final answer is 9999-99=9900
Answered by Cosmique
5

Answer:

Factors of:

15=3×5

25=5×5

45=3×3×5

LCM(15,25,45) = 3^2 × 5^2

= 9×25

= 225

The number divisible by these 15,25,45 exactly should be a multiple of 225 so,

225× p < 10000

( Since 10000 is the smallest 5 digit number)

p < 10000 / 225

p < 44.45

It means p should be smaller than 44.45

So, p should be 44 being the greatest natural number below 44.45

So.,

Largest no. Divisible by 15,25,45 will be

= 225 × 44

= 9900

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